A) 7th term
B) 5th term
C) 9th term
D) 11th term
Correct Answer: C
Solution :
The given arithmetic progression is 35, 30, 25, ..... Here, a = 35 and d = (-5). \[=\text{17}\times \text{23}=\text{391}\]term, \[=\text{2}\times \text{3}\times {{\text{5}}^{\text{2}}}\times \text{7}\times \text{l7}\times \text{23}=\text{41}0\text{55}0\] \[\pi \] For the first negative term, \[\frac{22}{7}\] \[\frac{22}{7}\] \[\pi \] \[\text{4}0={{\text{2}}^{\text{3}}}\times \text{5}\] \[\text{6}0={{\text{2}}^{\text{2}}}\times \text{3}\times \text{5}\] \[\therefore \] \[={{2}^{2}}\times 3\times 5\times 2=120\] \[f(p)={{\text{p}}^{\text{3}}}+\text{6}{{\text{p}}^{\text{2}}}+\text{lip}+\text{6}\] \[f(p)\]
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