A) \[\frac{n}{2}\]
B) \[\frac{n-1}{2}\]
C) \[\frac{n+1}{2}\]
D) \[\frac{n(n+1)}{{{n}^{2}}}\]
Correct Answer: B
Solution :
(1 + 1 + ....... 'n' terms) \[\text{6}0={{\text{2}}^{\text{2}}}\times \text{3}\times \text{5}\] \[\therefore \] \[={{2}^{2}}\times 3\times 5\times 2=120\] \[f(p)={{\text{p}}^{\text{3}}}+\text{6}{{\text{p}}^{\text{2}}}+\text{lip}+\text{6}\]
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