JEE Main & Advanced Mathematics Sequence & Series Question Bank Arithmetico - Geometric Series, Method of difference

  • question_answer
    \[1+\frac{3}{2}+\frac{5}{{{2}^{2}}}+\frac{7}{{{2}^{3}}}+......\,\infty \,\]is equal to [DCE 1999]

    A) 3

    B) 6

    C) 9

    D) 12

    Correct Answer: D

    Solution :

    It is an arithmetico-geometric series \[{{S}_{\infty }}=\frac{a}{1-r}+\frac{dr}{{{(1-r)}^{2}}}\]\[=\frac{1}{1-\frac{1}{2}}+\frac{2}{{{\left( 1-\frac{1}{2} \right)}^{2}}}\]\[=\frac{2}{\frac{1}{2}}+\frac{2}{\frac{1}{4}}\]                 \[=4+8=12\].


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