A) \[\frac{1}{b-a}+\frac{1}{b-c}=\frac{1}{b}\]
B) \[\frac{ac}{a+c}=b\]
C) \[\frac{b+a}{b-a}+\frac{b+c}{b-c}=1\]
D) None of these
Correct Answer: D
Solution :
\[a,\ b,\ c\] are in H.P. \[\Rightarrow \]\[b=\frac{2ac}{a+c}\] By inspection, we get (a) False (b) False (c) False
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