A) \[0.37\]moles
B) \[0.36\]moles
C) \[0.5\]moles
D) \[0.53\]moles
Correct Answer: B
Solution :
Atomic weight of zinc\[=65.38\,\,g\] Number of moles \[\text{=}\frac{\text{Given}\,\,\text{weight}\,\,\text{of}\,\,\text{element}}{\text{Given}\,\,\text{atomic}\,\,\text{weight}}\] \[\text{=}\frac{\text{23}\text{.3}}{\text{65}\text{.38}}\text{=0}\text{.36}\,\text{moles}\].
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