A) \[10\,\,g\]
B) \[20\,\,g\]
C) \[30\,\,g\]
D) \[40\,\,g\]
Correct Answer: A
Solution :
No. of atoms in\[3\,\,g\]of carbon\[=\]\[0.25\times \]Avogadro's number. The Weight of calcium which contains the same as those in a \[3g\] carbon\[=0.25\times GMW\]of\[Ca\]\[=0.25\times 40=10\,\,g\] \[\therefore \]The number of atoms present in\[3\] grams (\[0.4\] mole) of carbon is the same as in \[10\,\,g\] (\[0.4\]moles) of calcium.You need to login to perform this action.
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