A) \[Cu\]
B) \[Ag\]
C) \[Fe\]
D) \[Na\]
Correct Answer: B
Solution :
\[A{{g}_{2}}S+4NaCN\] ⇌ \[\underset{\text{Sodium}\,\,\text{dicyno}\,\,\text{argentate}}{\mathop{2Na\,\left[ Ag{{\left( CN \right)}_{2}} \right]+N{{a}_{2}}S}}\,\] \[2Na\,[Ag{{(CN)}_{2}}]+Zn\to \] \[\underset{\text{Sodium}\,\,\text{tetracyno}\,\,\text{zincate}\,\,\text{(ppt)}}{\mathop{N{{a}_{2}}\,[Zn\,{{(CN)}_{4}}]+2Ag\downarrow }}\,\]
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