A) \[{{K}^{+}}\]
B) \[C{{N}^{-}}\]
C) \[F{{e}^{3+}}\]
D) \[{{\left( CN \right)}_{6}}\]
Correct Answer: B
Solution :
\[{{K}_{3}}[Fe{{(CN)}_{6}}]\] because in it \[C{{N}^{-}}\] donats a lone pair of electron.
You need to login to perform this action.
You will be redirected in
3 sec
