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JEE Main & Advanced Mathematics Pair of Straight Lines Question Bank Bisectors of the angle between the lines, Point of intersection of the lines

  • question_answer
    If the bisectors of angles represented by \[a{{x}^{2}}+2hxy+b{{y}^{2}}=0\] and \[a'{{x}^{2}}+2h'xy+b'{{y}^{2}}=0\] are same, then

    A)            \[(a-b)h'=(a'-b')h\]           

    B)            \[(a-b)h=(a'-b')h'\]

    C)            \[(a+b)h'=(a'-b')h\]           

    D)            \[(a-b)h'=(a'+b')h\]

    Correct Answer: A

    Solution :

               Since bisectors are same, therefore \[\frac{a-b}{h}=\frac{a'-b'}{h'}\]                    Þ \[(a-b){h}'\,=({a}'-{b}')h\].


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