A) (2, 2)
B) (-2, -2)
C) (- 2, 2)
D) (2, -2)
Correct Answer: C
Solution :
Putting \[X=x+2,\ \ Y=y-2\] Equation becomes\[2{{X}^{2}}+3XY-2{{Y}^{2}}=0\] Which cuts at \[X=0,\ Y=0\] So, \[x+2=0,\ y-2=0\] Point of intersection\[(-2,2)\]. Trick: Only (-2, 2) is satisfying the given equation.You need to login to perform this action.
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