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JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques / कार्बनिक रसायन : कुछ मूलभूत सिद्धांत एवं तकन Question Bank Chemical analysis of organic compounds

  • question_answer
    An organic compound has C = 60%, H = 13.3% and O = 26.7%. Its empirical formula will be

    A) \[{{C}_{3}}{{H}_{6}}O\]

    B) \[{{C}_{2}}{{H}_{6}}{{O}_{2}}\]

    C) \[{{C}_{4}}{{H}_{8}}{{O}_{2}}\]

    D) \[{{C}_{3}}{{H}_{8}}O\]

    Correct Answer: D

    Solution :

    Elements                   No. of moles        Simple ratio
    C 60% 60/12 = 5 3.01
    H 13.3% 13.3/1 = 13.3 8.01
    O 26.7% 26.7/16 = 1.66 1
    Empirical formula = \[{{C}_{3}}{{H}_{8}}O\].


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