A) \[C{{l}_{2}}\] gets reduced to \[HCl\].
B) \[{{H}_{2}}S\] gets oxidized to S.
C) \[C{{l}_{2}}\] is the oxidizing agent.
D) \[{{H}_{2}}S\] is the oxidizing agent.
Correct Answer: D
Solution :
\[{{H}_{2}}S\] reduces \[C{{l}_{2}}\]to\[HCl.{{H}_{2}}S\] is the reducing agent.
You need to login to perform this action.
You will be redirected in
3 sec
