A) \[4N{{O}_{2}}\]
B) \[2N{{O}_{3}}\]
C) \[2PbN{{O}_{2}}\]
D) \[N{{O}_{2}}\]
Correct Answer: A
Solution :
When lead nitrate is heated, brown fumes are evolved, which is of \[N{{O}_{2}}\]. So, nA is \[4N{{O}_{2}}\].
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