A) 2 : 7
B) 7 : 2
C) 3 : 7
D) 7 : 3
Correct Answer: B
Solution :
Let \[a=3k,\,b=7k,\,c=8k\] \[\therefore \] \[s=\frac{1}{2}(a+b+c)=9k\] Then \[\frac{R}{r}=\frac{abc}{4\Delta }.\frac{s}{\Delta }=\frac{abc.s}{4s(s-a)\,(s-b)\,(s-c)}\] =\[\frac{3k\,.\,7k.\,8k}{4.\,6k\,.\,2k\,.\,k}=\frac{7}{2}\] i.e., \[R:r=7:2\].
You need to login to perform this action.
You will be redirected in
3 sec
