JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Circle connected with triangle

  • question_answer
    In an equilateral triangle of side \[2\sqrt{3}\]cm, the circum-radius is [EAMCET 1978]

    A) 1 cm

    B) \[\sqrt{3}\]cm

    C) 2 cm

    D) \[2\sqrt{3}\]cm

    Correct Answer: C

    Solution :

    \[a=b=c=2\sqrt{3}\] \[\Delta =\left( \frac{\sqrt{3}{{a}^{2}}}{4} \right)=3\sqrt{3}sq.\,cm,\,\text{ }\therefore \,R=\frac{abc}{4\Delta }=2cm\].


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