A) 80,000
B) 85,000
C) 85,100
D) 85,184
Correct Answer: D
Solution :
Population \[(P)=64,000,\] Annual Increase \[(r)=10%\] Hence, population after 3 years \[=64,000{{\left( 1+\frac{10}{100} \right)}^{3}}\] \[=64,000\times {{\left( \frac{11}{10} \right)}^{3}}\] \[=64,000\times \frac{11\times 11\times 11}{1000}\] \[=85,184\]
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