A) Rs. 10000
B) Rs. 12000
C) Rs. 13200
D) Rs. 11880
Correct Answer: B
Solution :
Let the principal at the end of first year be Rs. x. Then \[\frac{x\times 10\times 1}{100}=1320\] or \[x=13200\] Now, let the original principal be Rs. P. Then. amount after 1 year \[=P+\frac{P\times 10\times 1}{100}=\frac{11P}{10}\] \[\therefore \] \[\frac{11P}{10}=13200\] or \[P=\left( \frac{13200\times 10}{11} \right)=Rs.12000\]
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