A) Rs.120
B) Rs.104
C) Rs.116
D) Rs.122
Correct Answer: D
Solution :
We have \[A=P+I=P+\frac{PTR}{100}\] \[A-P=\frac{PTR}{100}\] \[So,\,\frac{{{A}_{1}}-{{P}_{1}}}{{{A}_{2}}-{{P}_{2}}}=\frac{{{P}_{1}}{{T}_{1}}{{R}_{1}}}{{{P}_{2}}{{T}_{2}}{{R}_{2}}}\] \[\Rightarrow \] \[\frac{95-85}{{{A}_{2}}-102}=\frac{85\times 3\times R}{102\times 5\times R}\] \[\Rightarrow \] \[{{A}_{2}}=102=20\Rightarrow {{A}_{2}}=Rs.\,122\]
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