A) Paramagnetic
B) Diamagnetic
C) Ferromagnetic
D) None
Correct Answer: A
Solution :
\[ZnS{{O}_{4}}\,\to \,Z{{n}^{++}}+SO_{4}^{-2}\] \[Z{{n}^{++}}\approx \,C{{u}^{++}}\] \[C{{u}^{+2}}\,\to \,3{{d}^{9}}-1\,\text{unpaired}\,\,\,{{e}^{-}}\] \ paramagnetic in nature.
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