A) \[Hg_{2}^{++}\]
B) \[H{{g}^{++}}\]
C) \[Hg{{I}_{2}}^{--}\]
D) \[Hg{{I}_{4}}^{--}\]
Correct Answer: D
Solution :
\[Hg{{I}_{2}}+2KI\,\to \,{{K}_{2}}[Hg{{I}_{4}}]\]⇌\[2{{K}^{+}}+{{[Hg{{I}_{4}}]}^{-\,-}}\]
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