A) \[FeO+Fe{{(OH)}_{2}}\]
B) \[F{{e}_{2}}{{O}_{3}}\]
C) \[F{{e}_{2}}{{O}_{3}}+Fe{{(OH)}_{2}}\]
D) \[F{{e}_{2}}{{O}_{3}}\] and \[Fe{{(OH)}_{3}}\]
Correct Answer: C
Solution :
Rust is \[F{{e}_{2}}{{O}_{3}}\]and \[Fe{{(OH)}_{3}}\]
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