A) \[Sb{{F}_{5}}\]
B) \[Mn{{F}_{3}}\]
C) \[KSb{{F}_{6}}\]
D) \[Mn{{F}_{4}}\]
Correct Answer: A
Solution :
\[{{K}_{2}}Mn{{F}_{6}}~+2Sb{{F}_{5}}\to 2KSb{{F}_{6}}+Mn{{F}_{3}}+\frac{1}{2}{{F}_{2}}\] In this reaction, the stronger Lewis acid\[Sb{{F}_{5}}\]displaces the weaker one,\[Mn{{F}_{4}}\]from its salt.\[Mn{{F}_{4}}\]is unstable and readily decomposes to give \[Mn{{F}_{3}}\]and fluorine.
You need to login to perform this action.
You will be redirected in
3 sec
