A) The white solid dissolves to form a colourless solution
B) The white solid dissolves to form a green solution
C) The white solid turns blue but does not dissolve
D) The white solid dissolves to form a blue solution
Correct Answer: D
Solution :
The white solid dissolves to form a blue solution. \[CuS{{O}_{4}}+\text{dil}\text{.}{{H}_{2}}S{{O}_{4}}\,\to \,\underset{\text{blue vitriol}}{\mathop{CuS{{O}_{4}}.5{{H}_{2}}O}}\,\]
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