A) \[N{{O}_{2}}\]is reduced in preference to \[{{H}_{3}}{{O}^{+}}\]
B) \[HN{{O}_{3}}\]is weaker acid than \[{{H}_{2}}S{{O}_{4}}\] and \[HCl\]
C) \[Zn\]acts as oxidising agent when reacts with \[HN{{O}_{3}}\]
D) In electrochemical series \[Zn\]is placed above the hydrogen
Correct Answer: B
Solution :
\[4Zn+10HN{{O}_{3}}\to 4Z{{(N{{O}_{3}})}_{2}}+N{{H}_{4}}N{{O}_{3}}+3{{H}_{2}}O\]
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