A) Copper
B) Silver
C) Nickel
D) Iron
Correct Answer: B
Solution :
\[A{{g}_{2}}S+4NaCN\to 2Na[Ag{{(CN)}_{2}}]+N{{a}_{2}}S\] \[2Na[Ag{{(CN)}_{2}}]+Zn\to N{{a}_{2}}[Zn{{(CN)}_{4}}]+2Ag\]
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