A) \[{{t}_{1}}{{t}_{2}}=1\]
B) \[{{t}_{1}}{{t}_{2}}=-1\]
C) \[{{t}_{1}}+{{t}_{2}}=1\]
D) \[{{t}_{1}}+{{t}_{2}}=-1\]
Correct Answer: B
Solution :
\[\frac{a-at_{2}^{2}}{at_{2}^{2}-at_{1}^{2}}=\frac{-2a{{t}_{2}}}{2a{{t}_{2}}-2a{{t}_{1}}}\] Þ \[(1-t_{2}^{2})=-{{t}_{2}}({{t}_{2}}+{{t}_{1}})\]or\[{{t}_{1}}{{t}_{2}}=-1\].
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