A) 0
B) 1
C) 2
D) - 1
Correct Answer: A
Solution :
Let a is the common root, so \[{{\alpha }^{2}}+p\alpha +q=0\] .....(i) and \[{{\alpha }^{2}}+q\alpha +p=0\] ....(ii) from (i) - (ii), \[\Rightarrow (p-q)\alpha +(q-p)=0\]\[\Rightarrow \alpha =1\] Put the value of \[\alpha \]in (i), \[p+q+1=0.\]You need to login to perform this action.
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