JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Condition for common roots, Quadratic expressions and Position of roots

  • question_answer
    Let  \[f(x)={{x}^{2}}+4x+1\]. Then

    A) \[f(x)>0\] for all x

    B) \[f(x)>1\] when \[x\ge 0\]

    C) \[f(x)\ge 1\] when \[x\le -4\]

    D) \[f(x)=f(-x)\] for all \[x\]

    Correct Answer: C

    Solution :

    Since f (x) is a quadratic expression having real roots. Therefore f (x) does not have the same sign for all x. \[f(x)\ge 1\Rightarrow {{x}^{2}}+4x+1\ge 1\,\Rightarrow {{x}^{2}}+4x\ge 0\]                                Þ \[x\le -4\]or \[x\ge 0\].


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