JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Conjugate, Modulus and Argument of complex number

  • question_answer
    A real value of x will satisfy the equation \[\left( \frac{3-4ix}{3+4ix} \right)=\] \[\alpha -i\beta \,(\alpha ,\beta \,\text{real),}\] if [Orissa JEE 2003]

    A) \[{{\alpha }^{2}}-{{\beta }^{2}}=-1\]

    B) \[{{\alpha }^{2}}-{{\beta }^{2}}=1\]

    C) \[{{\alpha }^{2}}+{{\beta }^{2}}=1\]

    D) \[{{\alpha }^{2}}-{{\beta }^{2}}=2\]

    Correct Answer: C

    Solution :

    \[\alpha -i\beta =\frac{3-4xi}{3+4xi}\]. Taking modulus and squaring on both sides, \[{{\alpha }^{2}}+{{\beta }^{2}}=1\].


You need to login to perform this action.
You will be redirected in 3 sec spinner