A) \[-{{60}^{o}}\]
B) \[{{60}^{o}}\]
C) \[{{120}^{o}}\]
D) \[-{{120}^{o}}\]
Correct Answer: C
Solution :
\[arg(-1+i\sqrt{3})={{\tan }^{-1}}\left( \frac{\sqrt{3}}{-1} \right)={{120}^{o}}\] because it lies in second quadrant.
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