A) \[\frac{\alpha }{2}\]
B) \[-\frac{\alpha }{2}\]
C) \[\frac{\pi }{2}+\frac{\alpha }{2}\]
D) \[\frac{\pi }{2}-\frac{\alpha }{2}\]
Correct Answer: D
Solution :
amp\[(z)={{\tan }^{-1}}\frac{\sin \alpha }{1-\cos \alpha }\] \[={{\tan }^{-1}}\left( \cot \frac{\alpha }{2} \right)={{\tan }^{-1}}\left\{ \tan \left( \frac{\pi }{2}-\frac{\alpha }{2} \right) \right\}=\frac{\pi }{2}-\frac{\alpha }{2}\].
You need to login to perform this action.
You will be redirected in
3 sec
