A) Straight line
B) Pair of straight lines
C) Circle
D) Ellipse
Correct Answer: B
Solution :
\[\sqrt{{{(x-3)}^{2}}+{{(y-1)}^{2}}}+\sqrt{{{(x+3)}^{2}}+{{(y-1)}^{2}}}=6\] \[\sqrt{{{(x-3)}^{2}}+{{(y-1)}^{2}}}=6-\sqrt{{{(x+3)}^{2}}+{{(y-1)}^{2}}}\] Squaring both sides. We get, \[12x+36=12\sqrt{{{(x+3)}^{2}}+{{(y-1)}^{2}}}\] Again squaring we get the given equation is pair of straight lines.You need to login to perform this action.
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