A) \[-\frac{2\pi }{3}\]
B) \[\frac{2\pi }{3}\]
C) \[\frac{4\pi }{3}\]
D) None of these
Correct Answer: D
Solution :
The principal value of \[{{\sin }^{-1}}\left[ \sin \left( \pi -\frac{2\pi }{3} \right) \right]\] \[={{\sin }^{-1}}\sin \left( \frac{\pi }{3} \right)=\frac{\pi }{3}\] .
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