A) 3
B) 1
C) 2
D) -1
Correct Answer: B
Solution :
Trick: According to given condition, we put \[p=q=r=\frac{1}{2}\]. Then,\[{{p}^{2}}+{{q}^{2}}+{{r}^{2}}+2pqr\] = \[{{\left( \frac{1}{2} \right)}^{2}}+{{\left( \frac{1}{2} \right)}^{2}}+{{\left( \frac{1}{2} \right)}^{2}}+2.\frac{1}{2}.\frac{1}{2}.\frac{1}{2}\] = \[\frac{1}{4}+\frac{1}{4}+\frac{1}{4}+\frac{2}{8}\]=1.You need to login to perform this action.
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