question_answer

The following reaction is described as [CBSE PMT 1997] \[\begin{matrix}    C{{H}_{3}}{{(C{{H}_{2}})}_{5}}  \\    {}  \\    {{H}_{3}}C  \\ \end{matrix}>\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,-Br\xrightarrow{OH}HO-\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,<\begin{matrix}    {{(C{{H}_{2}})}_{5}}C{{H}_{3}}  \\    {}  \\    C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,  \\ \end{matrix}\]

A) \[S{{E}^{2}}\]

B) \[S{{N}^{1}}\]

C) \[S{{N}^{2}}\]

D) \[S{{N}^{0}}\]

Correct Answer: C

Solution :

In this reaction inversion of configuration takes place this is called optical inversion. It is an example of \[S{{N}^{2}}\] reaction (Bimolecular Nucleophillic Substitution).