A) 70
B) 80
C) 90
D) 100
Correct Answer: C
Solution :
Mass of silver salt taken = 0.228 gm Mass of silver left = 0.162 gm Basicity of acid = 2 Step 1- To calculate the equivalent mass of the silver salt \[\frac{\text{Eq}\text{.}\,\,\text{mass}\,\,\text{of}\,\,\text{silver}\,\,\text{salt}}{\text{Eq}\text{.}\,\,\text{mass}\,\,\text{of}\,\,\text{silver}}=\frac{\text{Mass}\,\,\text{of}\,\,\text{Acid}\,\,\text{taken}}{\text{Mass}\,\,\text{of}\,\,\text{silver}\,\,\text{left}}\] \[=\frac{E}{108}=\frac{0.228}{0.162}\] \[=E=\frac{0.228}{0.162}\times 108=152\,(\text{Eq}\text{.}\,\,\text{mass}\,\,\text{of}\,\,\text{silver}\,\,\text{salt)}\] Step 2 - To calculate the eq. mass of acid. Eq. mass of acid = Eq. mass of silver salt - Eq. mass of Ag + Basicity = 152 - 108 + 1 = 152 - 109 = 43 (Eq. mass of acid) Step 3- To determine the molecular mass of acid. Mol. mass of the acid = Eq. mass of acid ´ basicity = 45 ´ 2 = 90.
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