A) \[{{C}_{5}}{{H}_{10}}{{O}_{5}}\]
B) \[{{C}_{3}}{{H}_{4}}{{O}_{3}}\]
C) \[{{C}_{12}}{{H}_{22}}{{O}_{11}}\]
D) \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]
Correct Answer: D
Solution :
\[\because \] 0.0833 mole carbohydrate has hydrogen = \[1g\] \[\therefore \] 1 mole carbohydrate has hydrogen \[=\frac{1}{0.0833}=12g\] Empirical Formula \[(C{{H}_{2}}O)\] has hydrogen \[=2g\] Hence \[n=\frac{12}{2}=6\] Hence molecular formula of carbohydrate \[={{(C{{H}_{2}}O)}_{6}}\] \[={{C}_{6}}{{H}_{12}}{{O}_{6}}\]
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