A) \[(2n+1)\frac{\pi }{4}\]
B) \[\frac{4}{(2n+1)\pi }\]
C) \[4\pi (2n+1)\]
D) None of these
Correct Answer: B
Solution :
\[\tan (\cot x)=\cot (\tan x)\] \[\Rightarrow \] \[\tan (\cot x)=\tan \left( \frac{\pi }{2}-\tan x \right)\] \[{{(70)}^{2}}+20h+{{h}^{2}}=(6)(70)(20)\] \[\cot x=n\pi +\frac{\pi }{2}-\tan x\Rightarrow \cot x+\tan x=n\pi +\frac{\pi }{2}\] \[{{(70)}^{2}}+20h+{{h}^{2}}=(6)(70)(20)\] \[\frac{2}{\sin 2x}=n\pi +\frac{\pi }{2}\Rightarrow \sin 2x=\frac{2}{n\pi +\frac{\pi }{2}}=\frac{4}{(2n+1)\pi }\].
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