A) \[{{\left[ Fe{{\left( {{H}_{2}}O \right)}_{6}} \right]}^{2+}}\]
B) \[{{\left[ Fe\left( NO \right)\text{ }{{\left( CN \right)}_{5}} \right]}^{2+}}\]
C) \[{{\left[ Fe{{\left( {{H}_{2}}O \right)}_{5}}NO \right]}^{2+}}\]
D) \[{{\left[ Fe\left( {{H}_{2}}O \right)\text{ }{{\left( NO \right)}_{5}} \right]}^{2+}}\]
Correct Answer: C
Solution :
The brown ring test for \[NO_{2}^{-}\] and \[NO_{3}^{-}\] is due to formation of \[{{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{2+}}\]
You need to login to perform this action.
You will be redirected in
3 sec
