A) Cationic part
B) Anionic part
C) Both in cationic and anionic parts
D) There is no zinc in the solution
Correct Answer: D
Solution :
\[Z{{n}^{2+}}+2NaOH\to Zn{{(OH)}_{2}}+2N{{a}^{+}}\] \[Zn{{(OH)}_{2}}+2NaOH\to N{{a}_{2}}Zn{{O}_{2}}+2{{H}_{2}}O.\]You need to login to perform this action.
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