A) p - electrons in Ne (at. no. = 10)
B) s - electrons in \[Mg\] (at. no. = 12)
C) d - electrons in \[Fe\]
D) p - electrons in \[C{{l}^{-}}\] (at. no. of \[Cl=17\])
Correct Answer: D
Solution :
p-electrons in \[C{{l}^{-}}\] (atomic no. of\[Cl=17\]) \[C{{l}^{-}}\,\to \,1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}\] \[F{{e}^{2+}}\,\to \,1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{6}}\] In \[F{{e}^{+2}}\] total number of \[d{{e}^{-}}=6\] which is not equal to \[p{{e}^{-}}\] in \[C{{l}^{-}}=12\].
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