A) 231x and \[\frac{231}{x}\]
B) \[462x\] and \[\frac{462}{x}\]
C) \[-462x\] and \[\frac{462}{x}\]
D) None of these
Correct Answer: C
Solution :
Middle term of \[{{\left( x-\frac{1}{x} \right)}^{11}}\]is \[{{T}_{6}}={{\,}^{11}}{{C}_{5}}{{(x)}^{6}}{{\left( -\frac{1}{x} \right)}^{5}}=-462\,x\] and \[{{T}_{7}}={{\,}^{11}}{{C}_{6}}{{(x)}^{5}}{{\left( -\frac{1}{x} \right)}^{6}}=\frac{462}{x}\]
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