A) \[N{{H}_{4}}N{{O}_{2}}\]
B) \[Na{{N}_{3}}\]
C) \[{{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}\]
D) All the three
Correct Answer: D
Solution :
\[N{{H}_{4}}N{{O}_{2}}\,\to \,{{N}_{2}}+2{{H}_{2}}O\] \[2Na{{N}_{3}}\,\to \,2Na+3{{N}_{2}}\] \[{{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}\,\to \,{{N}_{2}}+C{{r}_{2}}{{O}_{3}}+4{{H}_{2}}O\]
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