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8th Class Mathematics Cubes and Cube Roots Question Bank Cubes and Cube Roots

  • question_answer
    If \[x=\sqrt[3]{-3\frac{3}{8}},\].find the value of ?x'.

    A)  \[\frac{3}{2}\]                                  

    B)                         \[\frac{3}{4}\]                  

    C)                         \[-\frac{3}{4}\]                                

    D)                         \[-\frac{3}{2}\]

    Correct Answer: D

    Solution :

    \[\sqrt[3]{-3\frac{3}{8}}=\sqrt[3]{\frac{-27}{8}}=\sqrt[3]{\frac{-{{3}^{3}}}{{{2}^{3}}}}=\frac{-3}{2}\]


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