A) \[\frac{\sqrt{3}\,+i}{2}\]
B) \[\frac{\sqrt{3}\,-i}{2}\]
C) \[\frac{1+i\sqrt{3}}{2}\]
D) \[\frac{1-i\sqrt{3}}{2}\]
Correct Answer: A
Solution :
\[{{i}^{1/3}}={{\left( \cos \frac{\pi }{2}+i\sin \frac{\pi }{2} \right)}^{1/3}}=\cos \frac{\pi }{6}+i\sin \frac{\pi }{6}\]\[=\frac{\sqrt{3}}{2}+\frac{i}{2}\].
You need to login to perform this action.
You will be redirected in
3 sec
