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JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Definition of combinations, Conditional combinations, Division into groups, Derangements

  • question_answer
    Out of 10 white, 9 black and 7 red balls, the number of ways in which selection of one or more balls can be made, is

    A) 881

    B) 891

    C) 879

    D) 892

    Correct Answer: C

    Solution :

      The required number of ways are \[(10+1)(9+1)(7+1)-1=11\times 10\times 8-1=879\].


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