A) \[^{n}{{C}_{r}}\ p\ !\]
B) \[^{n-p}{{C}_{r}}\ r\ !\]
C) \[^{n-p}{{C}_{r-p}}\ r\ !\]
D) None of these
Correct Answer: C
Solution :
Since number of selections are \[^{n-p}{{C}_{r-p}}.\] Therefore the arrangement of r things can be done in r ! ways. Hence the total permutations are \[^{n-p}{{C}_{r-p}}\,r\,!\]
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