A) \[5\,\,!\,\,\times \,\,3\,\,!\]
B) \[^{4}{{P}_{3}}\times 5\,\,!\]
C) \[^{6}{{P}_{3}}\times 5\,\,!\]
D) \[^{5}{{P}_{3}}\times 3\,!\]
Correct Answer: C
Solution :
Since the 5 boys can sit in \[5\ !\] ways. In this case there are 6 places are vacant in which the girls can sit in \[^{6}{{P}_{3}}\] ways. Therefore required number of ways are\[^{6}{{P}_{3}}\times 5\ !\].
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