A) \[\frac{11\ !}{2\ !\ 2\ !}\]
B) \[\frac{11\ !}{2\ !}\]
C) \[\frac{11\ !}{2\ !\ 2\ !\ 2\ !}\]
D) \[11\ !\]
Correct Answer: C
Solution :
Since there are 2 M's, 2 A's and 2T's. \[\therefore \] Required number of ways are \[\frac{11\ !}{2\ !\ 2\ !\ 2\ !}\].
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