JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Definition of permutation, Number of permutations with or without repetition, Conditional permutations

  • question_answer
    How many numbers, lying between 99 and 1000 be made from the digits 2, 3, 7, 0, 8, 6 when the digits occur only once in each number [MP PET 1984]

    A) 100

    B) 90

    C) 120

    D) 80

    Correct Answer: A

    Solution :

    Required number of ways          = \[^{6}{{P}_{3}}{{-}^{5}}{{P}_{2}}=120-20=100\]. {Since between 99 and 1000, the numbers are of 3 digits, but those numbers should be omit in which ?0? comes at hundred place}.


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